What is the tangent of y= x/(sqrt(81+x^2)),(0,0) ?

The tangent of y= x/(sqrt(81+x^2)),(0,0) is y= 1/9 x

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tangent of y= x/(sqrt(81+x^2)),(0,0)

tangent of

y = \frac{x}{81 + x ^{2}}, (0, 0)

y = \frac{1}{9} x

Solution steps

Find the slope of

y = \frac{x}{81 + x ^{2}} : \frac{d y}{d x} = \frac{81}{( 81 + x ^{2} ) 81 + x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{9}

Find the line with slope m=

\frac{1}{9}

and passing through

(0, 0) : y = \frac{1}{9} x

y = \frac{1}{9} x

y^{^{''}} - 4 y^{^{'}} - 5 y = 0

a re a x + y^{2} = 42, x = y

\int_{0}^{\frac{π}{8}} x (sec (2 x))^{2} d x

\int arctan (9 t) d t

y^{^{'}} = - 2 y

What is the tangent of y= x/(sqrt(81+x^2)),(0,0) ?
The tangent of y= x/(sqrt(81+x^2)),(0,0) is y= 1/9 x