What is the derivative of 2x^7-3x^6+3x^3-4x^2-7 ?

The derivative of 2x^7-3x^6+3x^3-4x^2-7 is 14x^6-18x^5+9x^2-8x

What is the first derivative of 2x^7-3x^6+3x^3-4x^2-7 ?

The first derivative of 2x^7-3x^6+3x^3-4x^2-7 is 14x^6-18x^5+9x^2-8x

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\frac{d}{d x} (2 x^{7} - 3 x^{6} + 3 x^{3} - 4 x^{2} - 7)

14 x^{6} - 18 x^{5} + 9 x^{2} - 8 x

Solution steps

\frac{d}{d x} (2 x^{7} - 3 x^{6} + 3 x^{3} - 4 x^{2} - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{7}) - \frac{d}{d x} (3 x^{6}) + \frac{d}{d x} (3 x^{3}) - \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (7)

\frac{d}{d x} (2 x^{7}) = 14 x^{6}

\frac{d}{d x} (3 x^{6}) = 18 x^{5}

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (7) = 0

= 14 x^{6} - 18 x^{5} + 9 x^{2} - 8 x - 0

Simplify

= 14 x^{6} - 18 x^{5} + 9 x^{2} - 8 x

\int \frac{7 - 7 x}{1 - x} d x

\int x (x^{2} - 1)^{3} d x

d er i v a t i v e f (x) = 2 - 3 x

y^{^{'}} - 3 y = x y^{- 4}

d er i v a t i v e T 4 \frac{7}{9}

What is the derivative of 2x^7-3x^6+3x^3-4x^2-7 ?
The derivative of 2x^7-3x^6+3x^3-4x^2-7 is 14x^6-18x^5+9x^2-8x
What is the first derivative of 2x^7-3x^6+3x^3-4x^2-7 ?
The first derivative of 2x^7-3x^6+3x^3-4x^2-7 is 14x^6-18x^5+9x^2-8x