What is the derivative of a^9+cos^9(x) ?

The derivative of a^9+cos^9(x) is -9cos^8(x)sin(x)

What is the first derivative of a^9+cos^9(x) ?

The first derivative of a^9+cos^9(x) is -9cos^8(x)sin(x)

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derivative of

a^{9} + cos^{9} (x)

- 9 cos^{8} (x) sin (x)

Solution steps

\frac{d}{d x} (a^{9} + cos^{9} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a^{9}) + \frac{d}{d x} (cos^{9} (x))

\frac{d}{d x} (a^{9}) = 0

\frac{d}{d x} (cos^{9} (x)) = - 9 cos^{8} (x) sin (x)

= 0 - 9 cos^{8} (x) sin (x)

Simplify

= - 9 cos^{8} (x) sin (x)

\int \frac{( sec ^{2} ( \frac{1}{x} ) )}{x ^{2}} d x

\int t^{2} e^{- \frac{t}{2}} d t

\frac{d}{d x} (- 5 x^{2} - 4 cos (x))

\int 2 x e^{- 8 x} d x

n = 0 \sum \infty 300 (- 1.41)^{n}

What is the derivative of a^9+cos^9(x) ?
The derivative of a^9+cos^9(x) is -9cos^8(x)sin(x)
What is the first derivative of a^9+cos^9(x) ?
The first derivative of a^9+cos^9(x) is -9cos^8(x)sin(x)