u^{''}+0.25u^'+\H(t)=0

Lösung

u^{''} + 0.25 u^{'} + H (t (x)) = 0

0 + 0.25 \cdot 0 + H (t (x)) = 0

Schritte zur Lösung

u^{''} + 0.25 u^{'} + H (t (x)) = 0

u^{''} = 0

0 + 0.25 u^{^{'}} + H (t (x)) = 0

u^{'} = 0

0 + 0.25 \cdot 0 + H (t (x)) = 0

y^{^{'''}} - 23 y^{^{''}} + 160 y^{^{'}} - 300 y = 0

y^{^{''}} - 2 y^{^{'}} + 2 y = 0, y (π) = 7, y (0) = 7

l in e a r y^{^{''}} - 4 y^{^{'}} + 5 y = 0

y^{^{''}} + 5 y^{^{'}} + 5 y = 0

y^{^{''}} + 8 y^{^{'}} + 25 y = 0, y (0) = 2, y^{^{'}} (0) = - 7