r^{''}-4r^'-53r=0

Lösung

r^{''} - 4 r^{'} - 53 r = 0

r = 0

Schritte zur Lösung

r^{''} - 4 r^{'} - 53 r = 0

r^{''} = 0

0 - 4 r^{^{'}} - 53 r = 0

r^{'} = 0

0 - 4 \cdot 0 - 53 r = 0

0 - 4 \cdot 0 - 53 r = 0 : r = 0

r = 0

(D^{3} + 2 D^{2} + D + 2) y = 0

y^{^{''''}} - 4 y^{^{'''}} + 2 y^{^{''}} + 4 y^{^{'}} - 3 y = 0

y^{^{''''}} + y^{^{'''}} - 2 y^{^{''}} = 0

y^{^{'''}} - 6 y^{^{'}} + 11 y^{^{'}} - 6 y = 0

(D^{2} + 5 D + 6) y = 0