y^{''}+y^'+9.5y=0

Lösung

y^{^{''}} + y^{^{'}} + 9.5 y = 0

y = e^{- \frac{t}{2}} (c_{1} cos (\frac{37 t}{2}) + c_{2} sin (\frac{37 t}{2}))

Schritte zur Lösung

y^{''} (t) + y^{'} (t) + 9.5 y = 0

Solve linear ODE:

y = e^{- \frac{t}{2}} (c_{1} cos (\frac{37 t}{2}) + c_{2} sin (\frac{37 t}{2}))

y = e^{- \frac{t}{2}} (c_{1} cos (\frac{37 t}{2}) + c_{2} sin (\frac{37 t}{2}))

y^{^{''}} + 16 y = 0, y (π^{8}) = - 2, y^{^{'}} (π^{8}) = 16

y^{^{''}} - 3 y^{^{'}} - 4 y = 0, y (0) = 3, y (0) = 2

y^{^{''}} - \frac{10}{3} y^{^{'}} + α y = 0

(y^{^{''}} + 4 y)^{4} = 0

\frac{d ^{2} y}{d x ^{2}} + 0.25 \frac{d y}{d x} + 2 y = 0