What is the solution for y^{''}+5y^'-24y=0,y(0)=x,y^'(0)=56 ?

The solution for y^{''}+5y^'-24y=0,y(0)=x,y^'(0)=56 is y=c_{1}e^{3x}+c_{2}e^{-8x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+5y^'-24y=0,y(0)=x,y^'(0)=56

y^{^{''}} + 5 y^{^{'}} - 24 y = 0, y (0) = x, y^{^{'}} (0) = 56

y = c_{1} e^{3 x} + c_{2} e^{- 8 x}

Solution steps

y^{''} (x) + 5 y^{'} (x) - 24 y = 0

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{- 8 x}

y = c_{1} e^{3 x} + c_{2} e^{- 8 x}

y^{^{''}} - 9 y = 0, y (0) = 1, y^{^{'}} (0) = - 1

\frac{d ^{2} y}{d t ^{2}} + 4 y = 0

\frac{d ^{2} y}{d x ^{2}} + \frac{d y}{d x} - 6 y = 0

- 2 y^{^{''}} + 5 y^{^{'}} + 10 y = 0

y^{^{''}} + 2 y^{^{'}} - 8 y = 0, y (0) = 2, y^{^{'}} (0) = 16

What is the solution for y^{''}+5y^'-24y=0,y(0)=x,y^'(0)=56 ?
The solution for y^{''}+5y^'-24y=0,y(0)=x,y^'(0)=56 is y=c_{1}e^{3x}+c_{2}e^{-8x}