What is the solution for y^{''}-10y^'-144y=0,y(0)=11,y^'(0)=94 ?

The solution for y^{''}-10y^'-144y=0,y(0)=11,y^'(0)=94 is y=7e^{18t}+4e^{-8t}

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y^{''}-10y^'-144y=0,y(0)=11,y^'(0)=94

y^{^{''}} - 10 y^{^{'}} - 144 y = 0, y (0) = 11, y^{^{'}} (0) = 94

y = 7 e^{18 t} + 4 e^{- 8 t}

Solution steps

y^{''} (t) - 10 y^{'} (t) - 144 y = 0

Solve linear ODE:

y = 7 e^{18 t} + 4 e^{- 8 t}

y = 7 e^{18 t} + 4 e^{- 8 t}

y^{^{''}} - 6 y^{^{'}} + 13 y = 0, y (\frac{π}{4}) = 1, y (0) = 9

y^{^{''''}} + 3 y^{^{'''}} + 2 y^{^{''}} + 6 y^{^{'}} = 0

1 y^{^{''}} + 8 y^{^{'}} + 16 y = 0, y (0) = 3, y^{^{'}} (0) = - 7

(d^{3} - d^{2} - 12 d) y = 0

x^{^{''}} + 4 x^{^{'}} + 4 x = 0, x (0) = 0, x^{^{'}} (0) = 2

What is the solution for y^{''}-10y^'-144y=0,y(0)=11,y^'(0)=94 ?
The solution for y^{''}-10y^'-144y=0,y(0)=11,y^'(0)=94 is y=7e^{18t}+4e^{-8t}