Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
4y^{''}+5y^'-6y=01/8 y^{''}+4y^'+16y=0,y(0)=0,y^'(0)=92y^{'''}-y^{''}-y=0y^{''}-y=0,y(0)=e^xy^{''}-10y^'+25y=0,y(0)=e^{5x}
Frequently Asked Questions (FAQ)
What is the solution for 16y^{''}-32y^'+65y=0 ?
The solution for 16y^{''}-32y^'+65y=0 is y=e^t(c_{1}cos((7t)/4)+c_{2}sin((7t)/4))