What is the solution for y^{''}-16y=0,y(0)=1,y^{''}(0)=2 ?

The solution for y^{''}-16y=0,y(0)=1,y^{''}(0)=2 is y=(1-c_{2})e^{4t}+c_{2}e^{-4t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}-16y=0,y(0)=1,y^{''}(0)=2

y^{^{''}} - 16 y = 0, y (0) = 1, y^{^{''}} (0) = 2

y = (1 - c_{2}) e^{4 t} + c_{2} e^{- 4 t}

Solution steps

y^{''} (t) - 16 y = 0

Solve linear ODE:

y = (1 - c_{2}) e^{4 t} + c_{2} e^{- 4 t}

y = (1 - c_{2}) e^{4 t} + c_{2} e^{- 4 t}

What is the solution for y^{''}-16y=0,y(0)=1,y^{''}(0)=2 ?
The solution for y^{''}-16y=0,y(0)=1,y^{''}(0)=2 is y=(1-c_{2})e^{4t}+c_{2}e^{-4t}