What is the solution for y^{''}+49/3 y=0,y(0)= pi/8 ,y^'(0)=0 ?

The solution for y^{''}+49/3 y=0,y(0)= pi/8 ,y^'(0)=0 is y= pi/8 cos((7t)/(sqrt(3)))

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y^{''}+49/3 y=0,y(0)= pi/8 ,y^'(0)=0

y^{^{''}} + \frac{49}{3} y = 0, y (0) = \frac{π}{8}, y^{^{'}} (0) = 0

y = \frac{π}{8} cos (\frac{7 t}{3})

Solution steps

y^{''} (t) + \frac{49}{3} y = 0

Solve linear ODE:

y = \frac{π}{8} cos (\frac{7 t}{3})

y = \frac{π}{8} cos (\frac{7 t}{3})

What is the solution for y^{''}+49/3 y=0,y(0)= pi/8 ,y^'(0)=0 ?
The solution for y^{''}+49/3 y=0,y(0)= pi/8 ,y^'(0)=0 is y= pi/8 cos((7t)/(sqrt(3)))