What is the solution for 4y^{''}+(16)/(0.25)y=0 ?

The solution for 4y^{''}+(16)/(0.25)y=0 is y=c_{1}cos(4t)+c_{2}sin(4t)

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4y^{''}+(16)/(0.25)y=0

4 y^{^{''}} + \frac{16}{0.25} y = 0

y = c_{1} cos (4 t) + c_{2} sin (4 t)

Solution steps

4 y^{''} (t) + \frac{16}{0.25} y = 0

Solve linear ODE:

y = c_{1} cos (4 t) + c_{2} sin (4 t)

y = c_{1} cos (4 t) + c_{2} sin (4 t)

What is the solution for 4y^{''}+(16)/(0.25)y=0 ?
The solution for 4y^{''}+(16)/(0.25)y=0 is y=c_{1}cos(4t)+c_{2}sin(4t)