What is the solution for y^{'''}-9y^{''}+25y^'-17y=0 ?

The solution for y^{'''}-9y^{''}+25y^'-17y=0 is y=c_{1}e^t+e^{4t}(c_{2}cos(t)+c_{3}sin(t))

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y^{'''}-9y^{''}+25y^'-17y=0

y^{^{'''}} - 9 y^{^{''}} + 25 y^{^{'}} - 17 y = 0

y = c_{1} e^{t} + e^{4 t} (c_{2} cos (t) + c_{3} sin (t))

Solution steps

y^{'''} (t) - 9 y^{''} (t) + 25 y^{'} (t) - 17 y = 0

Solve linear ODE:

y = c_{1} e^{t} + e^{4 t} (c_{2} cos (t) + c_{3} sin (t))

y = c_{1} e^{t} + e^{4 t} (c_{2} cos (t) + c_{3} sin (t))

What is the solution for y^{'''}-9y^{''}+25y^'-17y=0 ?
The solution for y^{'''}-9y^{''}+25y^'-17y=0 is y=c_{1}e^t+e^{4t}(c_{2}cos(t)+c_{3}sin(t))