What is the solution for y^{''}+6y^'+9y=0,y(-1)=2,y^'(-1)=2 ?

The solution for y^{''}+6y^'+9y=0,y(-1)=2,y^'(-1)=2 is y=10e^{-3t-3}+8e^{-3t-3}t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+6y^'+9y=0,y(-1)=2,y^'(-1)=2

y^{^{''}} + 6 y^{^{'}} + 9 y = 0, y (- 1) = 2, y^{^{'}} (- 1) = 2

y = 10 e^{- 3 t - 3} + 8 e^{- 3 t - 3} t

Solution steps

y^{''} (t) + 6 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = 10 e^{- 3 t - 3} + 8 e^{- 3 t - 3} t

y = 10 e^{- 3 t - 3} + 8 e^{- 3 t - 3} t

What is the solution for y^{''}+6y^'+9y=0,y(-1)=2,y^'(-1)=2 ?
The solution for y^{''}+6y^'+9y=0,y(-1)=2,y^'(-1)=2 is y=10e^{-3t-3}+8e^{-3t-3}t