What is the solution for (d^2x)/(dt^2)+9.8x=0 ?

The solution for (d^2x)/(dt^2)+9.8x=0 is x=c_{1}cos((7t)/(sqrt(5)))+c_{2}sin((7t)/(sqrt(5)))

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(d^2x)/(dt^2)+9.8x=0

\frac{d ^{2} x}{d t ^{2}} + 9.8 x = 0

x = c_{1} cos (\frac{7 t}{5}) + c_{2} sin (\frac{7 t}{5})

Solution steps

\frac{d ^{2} x}{d t ^{2}} + 9.8 x = 0

Solve linear ODE:

x = c_{1} cos (\frac{7 t}{5}) + c_{2} sin (\frac{7 t}{5})

x = c_{1} cos (\frac{7 t}{5}) + c_{2} sin (\frac{7 t}{5})

What is the solution for (d^2x)/(dt^2)+9.8x=0 ?
The solution for (d^2x)/(dt^2)+9.8x=0 is x=c_{1}cos((7t)/(sqrt(5)))+c_{2}sin((7t)/(sqrt(5)))