What is the solution for y^{''}-4y^'+3y=0,y(0)=-2,y(0)=-14 ?

The solution for y^{''}-4y^'+3y=0,y(0)=-2,y(0)=-14 is y=(-2-c_{2})e^{3t}+c_{2}e^t

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y^{''}-4y^'+3y=0,y(0)=-2,y(0)=-14

y^{^{''}} - 4 y^{^{'}} + 3 y = 0, y (0) = - 2, y (0) = - 14

y = (- 2 - c_{2}) e^{3 t} + c_{2} e^{t}

Solution steps

y^{''} (t) - 4 y^{'} (t) + 3 y = 0

Solve linear ODE:

y = (- 2 - c_{2}) e^{3 t} + c_{2} e^{t}

y = (- 2 - c_{2}) e^{3 t} + c_{2} e^{t}

What is the solution for y^{''}-4y^'+3y=0,y(0)=-2,y(0)=-14 ?
The solution for y^{''}-4y^'+3y=0,y(0)=-2,y(0)=-14 is y=(-2-c_{2})e^{3t}+c_{2}e^t