What is the solution for u^{''}+7\H(t)=0,\H(0)=0,u^'(0)=7 ?

The solution for u^{''}+7\H(t)=0,\H(0)=0,u^'(0)=7 is u(t)=integral of integral of-7\H(t)

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u^{''}+7\H(t)=0,\H(0)=0,u^'(0)=7

u^{^{''}} + 7 H (t) = 0, H (0) = 0, u^{^{'}} (0) = 7

u (t) = \int \int - 7 H (t) d t d t

Solution steps

u^{''} (t) + 7 H (t) = 0

Isolate

u^{''} (t) : u^{''} (t) = - 7 H (t)

Solve

u^{''} (t) = - 7 H (t) : u^{'} (t) = \int - 7 H (t) d t

Solve

u^{'} (t) = \int - 7 H (t) d t : u (t) = \int \int - 7 H (t) d t d t

u (t) = \int \int - 7 H (t) d t d t

What is the solution for u^{''}+7\H(t)=0,\H(0)=0,u^'(0)=7 ?
The solution for u^{''}+7\H(t)=0,\H(0)=0,u^'(0)=7 is u(t)=integral of integral of-7\H(t)