What is the solution for x^{''}-x^'-110x=0,x(0)=14 ?

The solution for x^{''}-x^'-110x=0,x(0)=14 is x=(14-c_{2})e^{11t}+c_{2}e^{-10t}

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x^{''}-x^'-110x=0,x(0)=14

x^{^{''}} - x^{^{'}} - 110 x = 0, x (0) = 14

x = (14 - c_{2}) e^{11 t} + c_{2} e^{- 10 t}

Solution steps

x^{''} (t) - x^{'} (t) - 110 x = 0

Solve linear ODE:

x = (14 - c_{2}) e^{11 t} + c_{2} e^{- 10 t}

x = (14 - c_{2}) e^{11 t} + c_{2} e^{- 10 t}

What is the solution for x^{''}-x^'-110x=0,x(0)=14 ?
The solution for x^{''}-x^'-110x=0,x(0)=14 is x=(14-c_{2})e^{11t}+c_{2}e^{-10t}