What is the solution for y^{''}+36y^'=0,y(0)=1,y(0)=0 ?

The solution for y^{''}+36y^'=0,y(0)=1,y(0)=0 is y=1-c_{2}+c_{2}e^{-36t}

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y^{''}+36y^'=0,y(0)=1,y(0)=0

y^{^{''}} + 36 y^{^{'}} = 0, y (0) = 1, y (0) = 0

y = 1 - c_{2} + c_{2} e^{- 36 t}

Solution steps

y^{''} (t) + 36 y^{'} (t) = 0

Solve linear ODE:

y = 1 - c_{2} + c_{2} e^{- 36 t}

y = 1 - c_{2} + c_{2} e^{- 36 t}

What is the solution for y^{''}+36y^'=0,y(0)=1,y(0)=0 ?
The solution for y^{''}+36y^'=0,y(0)=1,y(0)=0 is y=1-c_{2}+c_{2}e^{-36t}