What is the solution for 2x^{''}+11x^'+5x=0 ?

The solution for 2x^{''}+11x^'+5x=0 is x=c_{1}e^{-t/2}+c_{2}e^{-5t}

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2x^{''}+11x^'+5x=0

2 x^{^{''}} + 11 x^{^{'}} + 5 x = 0

x = c_{1} e^{- \frac{t}{2}} + c_{2} e^{- 5 t}

Solution steps

2 x^{''} (t) + 11 x^{'} (t) + 5 x = 0

Solve linear ODE:

x = c_{1} e^{- \frac{t}{2}} + c_{2} e^{- 5 t}

x = c_{1} e^{- \frac{t}{2}} + c_{2} e^{- 5 t}

What is the solution for 2x^{''}+11x^'+5x=0 ?
The solution for 2x^{''}+11x^'+5x=0 is x=c_{1}e^{-t/2}+c_{2}e^{-5t}