What is the solution for 9y^{'''}+12y^{''}+4y^'=0 ?

The solution for 9y^{'''}+12y^{''}+4y^'=0 is y=c_{1}+c_{2}e^{-(2t)/3}+c_{3}e^{-(2t)/3}t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

9y^{'''}+12y^{''}+4y^'=0

9 y^{^{'''}} + 12 y^{^{''}} + 4 y^{^{'}} = 0

y = c_{1} + c_{2} e^{- \frac{2 t}{3}} + c_{3} e^{- \frac{2 t}{3}} t

Solution steps

9 y^{'''} (t) + 12 y^{''} (t) + 4 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- \frac{2 t}{3}} + c_{3} e^{- \frac{2 t}{3}} t

y = c_{1} + c_{2} e^{- \frac{2 t}{3}} + c_{3} e^{- \frac{2 t}{3}} t

What is the solution for 9y^{'''}+12y^{''}+4y^'=0 ?
The solution for 9y^{'''}+12y^{''}+4y^'=0 is y=c_{1}+c_{2}e^{-(2t)/3}+c_{3}e^{-(2t)/3}t