What is the solution for 100y^{''}+90y^'-162y=0 ?

The solution for 100y^{''}+90y^'-162y=0 is y=c_{1}e^{(9t}{10}}+c_{2}e^{-\frac{9t)/5}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

100y^{''}+90y^'-162y=0

100 y^{^{''}} + 90 y^{^{'}} - 162 y = 0

y = c_{1} e^{\frac{9 t}{10}} + c_{2} e^{- \frac{9 t}{5}}

Solution steps

100 y^{''} (t) + 90 y^{'} (t) - 162 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{9 t}{10}} + c_{2} e^{- \frac{9 t}{5}}

y = c_{1} e^{\frac{9 t}{10}} + c_{2} e^{- \frac{9 t}{5}}

What is the solution for 100y^{''}+90y^'-162y=0 ?
The solution for 100y^{''}+90y^'-162y=0 is y=c_{1}e^{(9t}{10}}+c_{2}e^{-\frac{9t)/5}