What is the solution for y^{''}+20y^'+92y=0 ?

The solution for y^{''}+20y^'+92y=0 is y=c_{1}e^{2(sqrt(2)-5)t}+c_{2}e^{-2(5+sqrt(2))t}

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y^{''}+20y^'+92y=0

y^{^{''}} + 20 y^{^{'}} + 92 y = 0

y = c_{1} e^{2 (2 - 5) t} + c_{2} e^{- 2 (5 + 2) t}

Solution steps

y^{''} (t) + 20 y^{'} (t) + 92 y = 0

Solve linear ODE:

y = c_{1} e^{2 (2 - 5) t} + c_{2} e^{- 2 (5 + 2) t}

y = c_{1} e^{2 (2 - 5) t} + c_{2} e^{- 2 (5 + 2) t}

What is the solution for y^{''}+20y^'+92y=0 ?
The solution for y^{''}+20y^'+92y=0 is y=c_{1}e^{2(sqrt(2)-5)t}+c_{2}e^{-2(5+sqrt(2))t}