What is the solution for y^{''}-6y^'-7y=0,y(0)=4,y^'(0)=4 ?

The solution for y^{''}-6y^'-7y=0,y(0)=4,y^'(0)=4 is y=e^{7t}+3e^{-t}

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y^{''}-6y^'-7y=0,y(0)=4,y^'(0)=4

y^{^{''}} - 6 y^{^{'}} - 7 y = 0, y (0) = 4, y^{^{'}} (0) = 4

y = e^{7 t} + 3 e^{- t}

Solution steps

y^{''} (t) - 6 y^{'} (t) - 7 y = 0

Solve linear ODE:

y = e^{7 t} + 3 e^{- t}

y = e^{7 t} + 3 e^{- t}

What is the solution for y^{''}-6y^'-7y=0,y(0)=4,y^'(0)=4 ?
The solution for y^{''}-6y^'-7y=0,y(0)=4,y^'(0)=4 is y=e^{7t}+3e^{-t}