What is the solution for y^{''}+2y^'-15y=0,y(0)=1 ?

The solution for y^{''}+2y^'-15y=0,y(0)=1 is y=(1-c_{2})e^{3t}+c_{2}e^{-5t}

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y^{''}+2y^'-15y=0,y(0)=1

y^{^{''}} + 2 y^{^{'}} - 15 y = 0, y (0) = 1

y = (1 - c_{2}) e^{3 t} + c_{2} e^{- 5 t}

Solution steps

y^{''} (t) + 2 y^{'} (t) - 15 y = 0

Solve linear ODE:

y = (1 - c_{2}) e^{3 t} + c_{2} e^{- 5 t}

y = (1 - c_{2}) e^{3 t} + c_{2} e^{- 5 t}

What is the solution for y^{''}+2y^'-15y=0,y(0)=1 ?
The solution for y^{''}+2y^'-15y=0,y(0)=1 is y=(1-c_{2})e^{3t}+c_{2}e^{-5t}