What is the solution for y^{''}-3y^'-18y=0,y(0)=24 ?

The solution for y^{''}-3y^'-18y=0,y(0)=24 is y=(24-c_{2})e^{6t}+c_{2}e^{-3t}

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y^{''}-3y^'-18y=0,y(0)=24

y^{^{''}} - 3 y^{^{'}} - 18 y = 0, y (0) = 24

y = (24 - c_{2}) e^{6 t} + c_{2} e^{- 3 t}

Solution steps

y^{''} (t) - 3 y^{'} (t) - 18 y = 0

Solve linear ODE:

y = (24 - c_{2}) e^{6 t} + c_{2} e^{- 3 t}

y = (24 - c_{2}) e^{6 t} + c_{2} e^{- 3 t}

What is the solution for y^{''}-3y^'-18y=0,y(0)=24 ?
The solution for y^{''}-3y^'-18y=0,y(0)=24 is y=(24-c_{2})e^{6t}+c_{2}e^{-3t}