Solution

Solution

Solution steps

Popular Examples

3y^{'''}-12y^'-4y^{''}=05y^{''}-13y^'-6y=0y^{''}+48y^'=0y^{''}+2ay^'+(a^2+1)y=0,y(0)=1,y^'(0)=06y^{''}-17y^'+12y=0

Frequently Asked Questions (FAQ)

  • What is 2u^{''}+7u^'-4\H(t)=0 ?

    The answer to 2u^{''}+7u^'-4\H(t)=0 is 2*0+7*0-4\H(t(x))=0