What is the solution for y^{''}+(1+n^2)y=0 ?

The solution for y^{''}+(1+n^2)y=0 is y=c_{1}e^{sqrt(-n^2-1)t}+c_{2}e^{-sqrt(-n^2-1)t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+(1+n^2)y=0

y^{^{''}} + (1 + n^{2}) y = 0

y = c_{1} e^{- n^{2} - 1 t} + c_{2} e^{- - n^{2} - 1 t}

Solution steps

y^{''} (t) + (1 + n^{2}) y = 0

Solve linear ODE:

y = c_{1} e^{- n^{2} - 1 t} + c_{2} e^{- - n^{2} - 1 t}

y = c_{1} e^{- n^{2} - 1 t} + c_{2} e^{- - n^{2} - 1 t}

What is the solution for y^{''}+(1+n^2)y=0 ?
The solution for y^{''}+(1+n^2)y=0 is y=c_{1}e^{sqrt(-n^2-1)t}+c_{2}e^{-sqrt(-n^2-1)t}