What is the solution for (d^2y)/(dt^2)+2(dy)/(dt)-15y=0 ?

The solution for (d^2y)/(dt^2)+2(dy)/(dt)-15y=0 is y=c_{1}e^{3t}+c_{2}e^{-5t}

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(d^2y)/(dt^2)+2(dy)/(dt)-15y=0

\frac{d ^{2} y}{d t ^{2}} + 2 \frac{d y}{d t} - 15 y = 0

y = c_{1} e^{3 t} + c_{2} e^{- 5 t}

Solution steps

\frac{d ^{2} y}{d t ^{2}} + 2 \frac{d y}{d t} - 15 y = 0

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{- 5 t}

y = c_{1} e^{3 t} + c_{2} e^{- 5 t}

What is the solution for (d^2y)/(dt^2)+2(dy)/(dt)-15y=0 ?
The solution for (d^2y)/(dt^2)+2(dy)/(dt)-15y=0 is y=c_{1}e^{3t}+c_{2}e^{-5t}