What is the solution for (D^3-D^2-4D+4)y=0 ?

The solution for (D^3-D^2-4D+4)y=0 is y=c_{1}e^x+c_{2}e^{-2x}+c_{3}e^{2x}

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(D^3-D^2-4D+4)y=0

(D^{3} - D^{2} - 4 D + 4) y = 0

y = c_{1} e^{x} + c_{2} e^{- 2 x} + c_{3} e^{2 x}

Solution steps

(D^{3} - D^{2} - 4 D + 4) y = 0

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- 2 x} + c_{3} e^{2 x}

y = c_{1} e^{x} + c_{2} e^{- 2 x} + c_{3} e^{2 x}

What is the solution for (D^3-D^2-4D+4)y=0 ?
The solution for (D^3-D^2-4D+4)y=0 is y=c_{1}e^x+c_{2}e^{-2x}+c_{3}e^{2x}