What is the solution for 9y^{''}-30y^'-24y=0,y(0)=0,y^'(0)=1 ?

The solution for 9y^{''}-30y^'-24y=0,y(0)=0,y^'(0)=1 is y= 3/14 e^{4t}-3/14 e^{-(2t)/3}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

9y^{''}-30y^'-24y=0,y(0)=0,y^'(0)=1

9 y^{^{''}} - 30 y^{^{'}} - 24 y = 0, y (0) = 0, y^{^{'}} (0) = 1

y = \frac{3}{14} e^{4 t} - \frac{3}{14} e^{- \frac{2 t}{3}}

Solution steps

9 y^{''} (t) - 30 y^{'} (t) - 24 y = 0

Solve linear ODE:

y = \frac{3}{14} e^{4 t} - \frac{3}{14} e^{- \frac{2 t}{3}}

y = \frac{3}{14} e^{4 t} - \frac{3}{14} e^{- \frac{2 t}{3}}

What is the solution for 9y^{''}-30y^'-24y=0,y(0)=0,y^'(0)=1 ?
The solution for 9y^{''}-30y^'-24y=0,y(0)=0,y^'(0)=1 is y= 3/14 e^{4t}-3/14 e^{-(2t)/3}