What is the solution for -5y^'+2y^{''}-y^'-6y=0 ?

The solution for -5y^'+2y^{''}-y^'-6y=0 is y=c_{1}e^{((3+sqrt(21))t)/2}+c_{2}e^{((3-sqrt(21))t)/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

-5y^'+2y^{''}-y^'-6y=0

- 5 y^{^{'}} + 2 y^{^{''}} - y^{^{'}} - 6 y = 0

y = c_{1} e^{\frac{( 3 + 21 ) t}{2}} + c_{2} e^{\frac{( 3 - 21 ) t}{2}}

Solution steps

- 5 y^{'} (t) + 2 y^{''} (t) - y^{'} (t) - 6 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{( 3 + 21 ) t}{2}} + c_{2} e^{\frac{( 3 - 21 ) t}{2}}

y = c_{1} e^{\frac{( 3 + 21 ) t}{2}} + c_{2} e^{\frac{( 3 - 21 ) t}{2}}

What is the solution for -5y^'+2y^{''}-y^'-6y=0 ?
The solution for -5y^'+2y^{''}-y^'-6y=0 is y=c_{1}e^{((3+sqrt(21))t)/2}+c_{2}e^{((3-sqrt(21))t)/2}