What is the solution for y^{''}-24y^'+12y=0 ?

The solution for y^{''}-24y^'+12y=0 is y=c_{1}e^{2(6+sqrt(33))t}+c_{2}e^{2(6-sqrt(33))t}

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y^{''}-24y^'+12y=0

y^{^{''}} - 24 y^{^{'}} + 12 y = 0

y = c_{1} e^{2 (6 + 33) t} + c_{2} e^{2 (6 - 33) t}

Solution steps

y^{''} (t) - 24 y^{'} (t) + 12 y = 0

Solve linear ODE:

y = c_{1} e^{2 (6 + 33) t} + c_{2} e^{2 (6 - 33) t}

y = c_{1} e^{2 (6 + 33) t} + c_{2} e^{2 (6 - 33) t}

What is the solution for y^{''}-24y^'+12y=0 ?
The solution for y^{''}-24y^'+12y=0 is y=c_{1}e^{2(6+sqrt(33))t}+c_{2}e^{2(6-sqrt(33))t}