What is the solution for y^{'''}+3y^{''}+y^'-205y=0 ?

The solution for y^{'''}+3y^{''}+y^'-205y=0 is y=c_{1}e^{5t}+e^{-4t}(c_{2}cos(5t)+c_{3}sin(5t))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{'''}+3y^{''}+y^'-205y=0

y^{^{'''}} + 3 y^{^{''}} + y^{^{'}} - 205 y = 0

y = c_{1} e^{5 t} + e^{- 4 t} (c_{2} cos (5 t) + c_{3} sin (5 t))

Solution steps

y^{'''} (t) + 3 y^{''} (t) + y^{'} (t) - 205 y = 0

Solve linear ODE:

y = c_{1} e^{5 t} + e^{- 4 t} (c_{2} cos (5 t) + c_{3} sin (5 t))

y = c_{1} e^{5 t} + e^{- 4 t} (c_{2} cos (5 t) + c_{3} sin (5 t))

What is the solution for y^{'''}+3y^{''}+y^'-205y=0 ?
The solution for y^{'''}+3y^{''}+y^'-205y=0 is y=c_{1}e^{5t}+e^{-4t}(c_{2}cos(5t)+c_{3}sin(5t))