What is the solution for (4D^2-4D+5)y=0 ?

The solution for (4D^2-4D+5)y=0 is y=e^{x/2}(c_{1}cos(x)+c_{2}sin(x))

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(4D^2-4D+5)y=0

(4 D^{2} - 4 D + 5) y = 0

y = e^{\frac{x}{2}} (c_{1} cos (x) + c_{2} sin (x))

Solution steps

(4 D^{2} - 4 D + 5) y = 0

Solve linear ODE:

y = e^{\frac{x}{2}} (c_{1} cos (x) + c_{2} sin (x))

y = e^{\frac{x}{2}} (c_{1} cos (x) + c_{2} sin (x))

What is the solution for (4D^2-4D+5)y=0 ?
The solution for (4D^2-4D+5)y=0 is y=e^{x/2}(c_{1}cos(x)+c_{2}sin(x))