What is the solution for y^{''}+y=0,y(pi/4)=0,y^'(pi/4)=-3 ?

The solution for y^{''}+y=0,y(pi/4)=0,y^'(pi/4)=-3 is y= 3/(sqrt(2))cos(t)-3/(sqrt(2))sin(t)

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y^{''}+y=0,y(pi/4)=0,y^'(pi/4)=-3

y^{^{''}} + y = 0, y (\frac{π}{4}) = 0, y^{^{'}} (\frac{π}{4}) = - 3

y = \frac{3}{2} cos (t) - \frac{3}{2} sin (t)

Solution steps

y^{''} (t) + y = 0

Solve linear ODE:

y = \frac{3}{2} cos (t) - \frac{3}{2} sin (t)

y = \frac{3}{2} cos (t) - \frac{3}{2} sin (t)

What is the solution for y^{''}+y=0,y(pi/4)=0,y^'(pi/4)=-3 ?
The solution for y^{''}+y=0,y(pi/4)=0,y^'(pi/4)=-3 is y= 3/(sqrt(2))cos(t)-3/(sqrt(2))sin(t)