What is the solution for 121y^{''}-4y=0 ?

The solution for 121y^{''}-4y=0 is y=c_{1}e^{(2t)/(11)}+c_{2}e^{-(2t)/(11)}

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121y^{''}-4y=0

121 y^{^{''}} - 4 y = 0

y = c_{1} e^{\frac{2 t}{11}} + c_{2} e^{- \frac{2 t}{11}}

Solution steps

121 y^{''} (t) - 4 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{2 t}{11}} + c_{2} e^{- \frac{2 t}{11}}

y = c_{1} e^{\frac{2 t}{11}} + c_{2} e^{- \frac{2 t}{11}}

What is the solution for 121y^{''}-4y=0 ?
The solution for 121y^{''}-4y=0 is y=c_{1}e^{(2t)/(11)}+c_{2}e^{-(2t)/(11)}