What is the solution for y^{''}-4y^'-5y=0,y(1)=0 ?

The solution for y^{''}-4y^'-5y=0,y(1)=0 is y=-c_{2}e^{5t-6}+c_{2}e^{-t}

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y^{''}-4y^'-5y=0,y(1)=0

y^{^{''}} - 4 y^{^{'}} - 5 y = 0, y (1) = 0

y = - c_{2} e^{5 t - 6} + c_{2} e^{- t}

Solution steps

y^{''} (t) - 4 y^{'} (t) - 5 y = 0

Solve linear ODE:

y = - c_{2} e^{5 t - 6} + c_{2} e^{- t}

y = - c_{2} e^{5 t - 6} + c_{2} e^{- t}

What is the solution for y^{''}-4y^'-5y=0,y(1)=0 ?
The solution for y^{''}-4y^'-5y=0,y(1)=0 is y=-c_{2}e^{5t-6}+c_{2}e^{-t}