2y^{''}-3y^'+1/2 y=0

Lösung

2 y^{^{''}} - 3 y^{^{'}} + \frac{1}{2} y = 0

y = c_{1} e^{\frac{( 3 + 5 ) t}{4}} + c_{2} e^{\frac{( 3 - 5 ) t}{4}}

Schritte zur Lösung

2 y^{''} (t) - 3 y^{'} (t) + \frac{1}{2} y = 0

Solve linear ODE:

y = c_{1} e^{\frac{( 3 + 5 ) t}{4}} + c_{2} e^{\frac{( 3 - 5 ) t}{4}}

y = c_{1} e^{\frac{( 3 + 5 ) t}{4}} + c_{2} e^{\frac{( 3 - 5 ) t}{4}}