What is the solution for y^{''}-3y^'-10y=0,y(0)=1 ?

The solution for y^{''}-3y^'-10y=0,y(0)=1 is y=(1-c_{2})e^{5t}+c_{2}e^{-2t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}-3y^'-10y=0,y(0)=1

y^{^{''}} - 3 y^{^{'}} - 10 y = 0, y (0) = 1

y = (1 - c_{2}) e^{5 t} + c_{2} e^{- 2 t}

Solution steps

y^{''} (t) - 3 y^{'} (t) - 10 y = 0

Solve linear ODE:

y = (1 - c_{2}) e^{5 t} + c_{2} e^{- 2 t}

y = (1 - c_{2}) e^{5 t} + c_{2} e^{- 2 t}

What is the solution for y^{''}-3y^'-10y=0,y(0)=1 ?
The solution for y^{''}-3y^'-10y=0,y(0)=1 is y=(1-c_{2})e^{5t}+c_{2}e^{-2t}