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Beliebt Rechnen >

2y^{''}+6y^'+8y=0

Lösung

2 y^{^{''}} + 6 y^{^{'}} + 8 y = 0

Lösung

y = e^{- \frac{3 t}{2}} (c_{1} cos (\frac{7 t}{2}) + c_{2} sin (\frac{7 t}{2}))

Schritte zur Lösung

2 y^{''} (t) + 6 y^{'} (t) + 8 y = 0

Solve linear ODE:

y = e^{- \frac{3 t}{2}} (c_{1} cos (\frac{7 t}{2}) + c_{2} sin (\frac{7 t}{2}))

y = e^{- \frac{3 t}{2}} (c_{1} cos (\frac{7 t}{2}) + c_{2} sin (\frac{7 t}{2}))

Graph

Beliebte Beispiele

y^{'''}-y^{''}+2y^'-2y=0

y^{^{'''}} - y^{^{''}} + 2 y^{^{'}} - 2 y = 0

- 2 y^{^{''}} + y = 0

y^{''}-3y^'-4y=0,y(0)=3,y^'(0)=2

y^{^{''}} - 3 y^{^{'}} - 4 y = 0, y (0) = 3, y^{^{'}} (0) = 2

y^{''}+16y=0,y(0)=1,y^'(0)=0

y^{^{''}} + 16 y = 0, y (0) = 1, y^{^{'}} (0) = 0

y^{''}+11y^'-12y=0

y^{^{''}} + 11 y^{^{'}} - 12 y = 0