What is the solution for y^{''}+5y^'+6y=0,y(0)=0,y^'(0)=1 ?

The solution for y^{''}+5y^'+6y=0,y(0)=0,y^'(0)=1 is y=e^{-2t}-e^{-3t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+5y^'+6y=0,y(0)=0,y^'(0)=1

y^{^{''}} + 5 y^{^{'}} + 6 y = 0, y (0) = 0, y^{^{'}} (0) = 1

y = e^{- 2 t} - e^{- 3 t}

Solution steps

y^{''} (t) + 5 y^{'} (t) + 6 y = 0

Solve linear ODE:

y = e^{- 2 t} - e^{- 3 t}

y = e^{- 2 t} - e^{- 3 t}

What is the solution for y^{''}+5y^'+6y=0,y(0)=0,y^'(0)=1 ?
The solution for y^{''}+5y^'+6y=0,y(0)=0,y^'(0)=1 is y=e^{-2t}-e^{-3t}