What is the solution for 100y^{''}+200y^'+101y=0 ?

The solution for 100y^{''}+200y^'+101y=0 is y=e^{-t}(c_{1}cos(t/(10))+c_{2}sin(t/(10)))

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100y^{''}+200y^'+101y=0

100 y^{^{''}} + 200 y^{^{'}} + 101 y = 0

y = e^{- t} (c_{1} cos (\frac{t}{10}) + c_{2} sin (\frac{t}{10}))

Solution steps

100 y^{''} (t) + 200 y^{'} (t) + 101 y = 0

Solve linear ODE:

y = e^{- t} (c_{1} cos (\frac{t}{10}) + c_{2} sin (\frac{t}{10}))

y = e^{- t} (c_{1} cos (\frac{t}{10}) + c_{2} sin (\frac{t}{10}))

What is the solution for 100y^{''}+200y^'+101y=0 ?
The solution for 100y^{''}+200y^'+101y=0 is y=e^{-t}(c_{1}cos(t/(10))+c_{2}sin(t/(10)))