Solution
Solution
Solution steps
Solve linear ODE:
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Frequently Asked Questions (FAQ)
What is the solution for 3y^{''}+2y^'-8y=0,y(0)=-6,y^'(0)=-18 ?
The solution for 3y^{''}+2y^'-8y=0,y(0)=-6,y^'(0)=-18 is y=-9e^{(4t)/3}+3e^{-2t}