What is the solution for y^{''}+4y=0,y(pi/6)=5,y(0)=-2 ?

The solution for y^{''}+4y=0,y(pi/6)=5,y(0)=-2 is y=-2cos(2t)+4sqrt(3)sin(2t)

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y^{''}+4y=0,y(pi/6)=5,y(0)=-2

y^{^{''}} + 4 y = 0, y (\frac{π}{6}) = 5, y (0) = - 2

y = - 2 cos (2 t) + 43 sin (2 t)

Solution steps

y^{''} (t) + 4 y = 0

Solve linear ODE:

y = - 2 cos (2 t) + 43 sin (2 t)

y = - 2 cos (2 t) + 43 sin (2 t)

What is the solution for y^{''}+4y=0,y(pi/6)=5,y(0)=-2 ?
The solution for y^{''}+4y=0,y(pi/6)=5,y(0)=-2 is y=-2cos(2t)+4sqrt(3)sin(2t)