What is the solution for (D^3+D^2+4D+4)y=0 ?

The solution for (D^3+D^2+4D+4)y=0 is y=c_{1}e^{-x}+c_{2}cos(2x)+c_{3}sin(2x)

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(D^3+D^2+4D+4)y=0

(D^{3} + D^{2} + 4 D + 4) y = 0

y = c_{1} e^{- x} + c_{2} cos (2 x) + c_{3} sin (2 x)

Solution steps

(D^{3} + D^{2} + 4 D + 4) y = 0

Solve linear ODE:

y = c_{1} e^{- x} + c_{2} cos (2 x) + c_{3} sin (2 x)

y = c_{1} e^{- x} + c_{2} cos (2 x) + c_{3} sin (2 x)

What is the solution for (D^3+D^2+4D+4)y=0 ?
The solution for (D^3+D^2+4D+4)y=0 is y=c_{1}e^{-x}+c_{2}cos(2x)+c_{3}sin(2x)