What is the solution for y^{''}-4y^'+4y=0,y(0)=1,y^'(0)=5 ?

The solution for y^{''}-4y^'+4y=0,y(0)=1,y^'(0)=5 is y=e^{2t}+3e^{2t}t

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y^{''}-4y^'+4y=0,y(0)=1,y^'(0)=5

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = 1, y^{^{'}} (0) = 5

y = e^{2 t} + 3 e^{2 t} t

Solution steps

y^{''} (t) - 4 y^{'} (t) + 4 y = 0

Solve linear ODE:

y = e^{2 t} + 3 e^{2 t} t

y = e^{2 t} + 3 e^{2 t} t

What is the solution for y^{''}-4y^'+4y=0,y(0)=1,y^'(0)=5 ?
The solution for y^{''}-4y^'+4y=0,y(0)=1,y^'(0)=5 is y=e^{2t}+3e^{2t}t