Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
2y^{''}+8y^'+80y=0,y(0)=0,y^'(0)=0y^{'''}-2y^{''}-5y^'+6y=02y^{''}+20y^'+51y=0,y(0)=2,y^'(0)=02y^{''}-y^'-y=03y^{''}+11y^'-7y=0
Frequently Asked Questions (FAQ)
What is the solution for 2y^{''}-5y^'+2y=0 ?
The solution for 2y^{''}-5y^'+2y=0 is y=c_{1}e^{2t}+c_{2}e^{t/2}