What is the solution for (d^2x)/(dt^2)+5(dx)/(dt)+4x=0 ?

The solution for (d^2x)/(dt^2)+5(dx)/(dt)+4x=0 is x=c_{1}e^{-t}+c_{2}e^{-4t}

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(d^2x)/(dt^2)+5(dx)/(dt)+4x=0

\frac{d ^{2} x}{d t ^{2}} + 5 \frac{d x}{d t} + 4 x = 0

x = c_{1} e^{- t} + c_{2} e^{- 4 t}

Solution steps

\frac{d ^{2} x}{d t ^{2}} + 5 \frac{d x}{d t} + 4 x = 0

Solve linear ODE:

x = c_{1} e^{- t} + c_{2} e^{- 4 t}

x = c_{1} e^{- t} + c_{2} e^{- 4 t}

What is the solution for (d^2x)/(dt^2)+5(dx)/(dt)+4x=0 ?
The solution for (d^2x)/(dt^2)+5(dx)/(dt)+4x=0 is x=c_{1}e^{-t}+c_{2}e^{-4t}