What is the solution for (D^5+8D^3+16D)y=0 ?

The solution for (D^5+8D^3+16D)y=0 is y=c_{1}+c_{2}cos(2x)+c_{3}sin(2x)+x(c_{4}cos(2x)+c_{5}sin(2x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(D^5+8D^3+16D)y=0

(D^{5} + 8 D^{3} + 16 D) y = 0

y = c_{1} + c_{2} cos (2 x) + c_{3} sin (2 x) + x (c_{4} cos (2 x) + c_{5} sin (2 x))

Solution steps

(D^{5} + 8 D^{3} + 16 D) y = 0

Solve linear ODE:

y = c_{1} + c_{2} cos (2 x) + c_{3} sin (2 x) + x (c_{4} cos (2 x) + c_{5} sin (2 x))

y = c_{1} + c_{2} cos (2 x) + c_{3} sin (2 x) + x (c_{4} cos (2 x) + c_{5} sin (2 x))

What is the solution for (D^5+8D^3+16D)y=0 ?
The solution for (D^5+8D^3+16D)y=0 is y=c_{1}+c_{2}cos(2x)+c_{3}sin(2x)+x(c_{4}cos(2x)+c_{5}sin(2x))